传销策划

MO&Co.摩安珂品牌。传销的方法

时间:2019-11-23 00:00

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品牌传销策划公司」
刻骨理解区块链最好的方式人生最悲哀的莫过于亲手搭建一个。在这个过程中理解它背后作文600字的逻辑和原理。
接上一篇《学习区块链的最好方法是构建一个(上)》第三步:与我们的区块链交互你可以使用普通的cURL或Postman工具,通过网络与我们的API进行交互。启动检波器:
1.? ??$?python?blockchain.py2.? ? ?*?Running?on?http://127.0.0.1:5000/?(Press?CTRL+C?to?quit)
让我们尝试通过向http://localhost:5000/mine发出GET请求来挖掘一个区块:UsingPostman to make a GET?request让我们通过向http://localhost:5000/transactions/new? 发出一个POST请求来创建一个新的交易,这个交易包含了交易结构的主体:UsingPostman to make a POST?request如果你不使用 Postman 工具,同样可以使用cURL这个工具来实现同样的目的:
1.?????????????$?curl?-X?POST?-H?“Content-Type:?application/json”?-d?‘{2.??????????????“sender”:?“d4ee26eee15148ee92c6cd394edd974e”,3.??????????????“recipient”:?“someone-other-address”,4.??????????????“amount”:?55.?????????????}’?“http://localhost:5000/transactions/new”
重启了我的检波器,并挖掘了两个区块,总共给出了3个区块。让我们通过请求http://localhost:5000/chain检讨书整个链:
1.?????????????{2.???????????????“chain”:?[3.?????????????????{4.???????????????????“index”:?1,5.???????????????????“previous_hash”:?1,6.???????????????????“proof”:?100,7.???????????????????“timestamp”:?1506280650.770839,8.???????????????????“transactions”:?[]9.?????????????????},10.??????????????{11.?????????????????“index”:?2,12.????????????????“previous_hash”:?“c099bc…bfb7”,13.????????????????“proof”:?35293,14.????????????????“timestamp”:?1506280664.717925,15.????????????????“transactions”:?[16.??????????????????{17.????????????????????“amount”:?1,18.????????????????????“recipient”:?“8bbcb347e0634905b0cac7955bae152b”,19.????????????????????“sender”:?“0”20.??????????????????}21.????????????????]22.??????????????},23.??????????????{24.????????????????“index”:?3,25.????????????????“previous_hash”:?“eff91a…10f2”,26.????????????????“proof”:?35089,27.????????????????“timestamp”:?1506280666.1086972,28.????????????????“transactions”:?[29.??????????????????{30.????????????????????“amount”:?1,31.????????????????????“recipient”:?“8bbcb347e0634905b0cac7955bae152b”,32.????????????????????“sender”:?“0”33.??????????????????}34.????????????????]35.??????????????}36.????????????],37.????????????“length”:?338.??????????}
第四步:共识这非常酷。我们有一个基本的 Blockchain 接受交易,它同意我们挖掘新的区块。但 Blockchain 的关键在于,它们应该是分布式光纤的。如果它们是分布式光纤的,我们什么担保它们都在一条链?这被称为共识的问题,如果我们想要在我们的网络中有多个节点。我们就必须实现一个共识的算法。报了名新节点在实现共识算法之前。我们需要一种方法让节点知道网络上的相邻节点。我们网络上的每个节点都应该保留网络上另外节点的报了名表编辑器。我们需要更多的端点:
1.?/nodes/register?以url的形式接受新的节点列表。2.??/nodes/resolve?? 来实现我们的共识算法,它可以解决任何冲突——以担保一个节点拥有正确的链。
我们需要修改 Blockchain 的构造函数,并提供报了名节点的方法:
1.?????????????…2.?????????????from?urllib.parse?import?urlparse3.?????????????…4.5.6.?????????????class?Blockchain(object):7.?????????????????def?__init__(self):8.?????????????????????…9.?????????????????????self.nodes?=?set()10.??????????????????…11.12.??????????????def?register_node(self,?address):13.??????????????????“””14.??????????????????Add?a?new?node?to?the?list?of?nodes15.16.??????????????????:param?address:?<str>?Address?of?node.?Eg.?‘http://192.168.0.5:5000’17.??????????????????:return:?None18.??????????????????“””19.20.??????????????????parsed_url?=?urlparse(address)21.??????????????????self.nodes.add(parsed_url.netloc)Amethod for adding neighbouring nodes to our Network
使用set()来保存节点列表。这是担保新节点的添加兼备幂等性的廉价方式。这表示无论我们添加多少次特定节点,它都只会产出一次。实现算法的共识如前所街道述,当一个节点与另一个节点兼备不同链时就有了冲突。为了解决这个问题,我们制定一条规则:最长的与此同时有效的链才是权威的。网络上最长的链是事实上的英文的链。动用该算法。我们在网络节点之间达成了一致。
1.?????????????…2.?????????????import?requests3.4.5.?????????????class?Blockchain(object)6.?????????????????…7.8.?????????????????def?valid_chain(self,?chain):9.?????????????????????“””10.??????????????????Determine?if?a?given?blockchain?is?valid11.12.??????????????????:param?chain:?<list>?A?blockchain13.??????????????????:return:?<bool>?True?if?valid,?False?if?not14.??????????????????“””15.16.??????????????????last_block?=?chain[0]17.??????????????????current_index?=?118.19.??????????????????while?current_index?<?len(chain):20.??????????????????????block?=?chain[current_index]21.??????????????????????print(f'{last_block}’)22.??????????????????????print(f'{block}’)23.??????????????????????print(“\n———–\n”)24.??????????????????????#?Check?that?the?hash?of?the?block?is?correct25.??????????????????????if?block[‘previous_hash’]?!=?self.hash(last_block):26.??????????????????????????return?False27.28.??????????????????????#?Check?that?the?Proof?of?Work?is?correct29.??????????????????????if?not?self.valid_proof(last_block[‘proof’],?block[‘proof’]):30.??????????????????????????return?False31.32.??????????????????????last_block?=?block33.??????????????????????current_index?+=?134.35.??????????????????return?True36.37.??????????????def?resolve_conflicts(self):38.??????????????????“””39.??????????????????This?is?our?Consensus?Algorithm,?it?resolves?conflicts40.??????????????????by?replacing?our?chain?with?the?longest?one?in?the?network.41.42.??????????????????:return:?<bool>?True?if?our?chain?was?replaced,?False?if?not43.??????????????????“””44.45.??????????????????neighbours?=?self.nodes46.??????????????????new_chain?=?None47.48.??????????????????#?We’re?only?looking?for?chains?longer?than?ours49.??????????????????max_length?=?len(self.chain)50.51.??????????????????#?Grab?and?verify?the?chains?from?all?the?nodes?in?our?network52.??????????????????for?node?in?neighbours:53.??????????????????????response?=?requests.get(f’http://{node}/chain’)54.55.??????????????????????if?response.status_code?==?200:56.??????????????????????????length?=?response.json()[‘length’]57.??????????????????????????chain?=?response.json()[‘chain’]58.59.??????????????????????????#?Check?if?the?length?is?longer?and?the?chain?is?valid60.??????????????????????????if?length?>?max_length?and?self.valid_chain(chain):61.??????????????????????????????max_length?=?length62.??????????????????????????????new_chain?=?chain63.64.??????????????????#?Replace?our?chain?if?we?discovered?a?new,?valid?chain?longer?than?ours65.??????????????????if?new_chain:66.??????????????????????self.chain?=?new_chain67.??????????????????????return?True68.69.??????????????????return?False
第一个方法valid_chain() 动真格检讨书链是否有效,通过循环遍历每个区块并验证哈希和证书。resolve_conflicts() 是这么一个方法:它遍历我们所有的近旁节点,载入它们的链并使用上面的方法验证它们。如果一个有效的链被发现,它的长度大于我们的,我们就替换掉我们当前所街道使用的链。让我们将两个端点报了名到API中,一个用于添加相邻节点,另一个用于解决冲突:
1.?????????????@app.route(‘/nodes/register’,?methods=[‘POST’])2.?????????????def?register_nodes():3.?????????????????values?=?request.get_json()4.5.?????????????????nodes?=?values.get(‘nodes’)6.?????????????????if?nodes?is?None:7.?????????????????????return?“Error:?Please?supply?a?valid?list?of?nodes”,?4008.9.?????????????????for?node?in?nodes:10.??????????????????blockchain.register_node(node)11.12.??????????????response?=?{13.??????????????????‘message’:?‘New?nodes?have?been?added’,14.??????????????????‘total_nodes’:?list(blockchain.nodes),15.??????????????}16.??????????????return?jsonify(response),?20117.18.19.??????????@app.route(‘/nodes/resolve’,?methods=[‘GET’])20.??????????def?consensus():21.??????????????replaced?=?blockchain.resolve_conflicts()22.23.??????????????if?replaced:24.??????????????????response?=?{25.??????????????????????‘message’:?‘Our?chain?was?replaced’,26.??????????????????????‘new_chain’:?blockchain.chain27.??????????????????}28.??????????????else:29.??????????????????response?=?{30.??????????????????????‘message’:?‘Our?chain?is?authoritative’,31.??????????????????????‘chain’:?blockchain.chain32.??????????????????}33.34.??????????????return?jsonify(response),?200
这时,你可以使用不同的机器,并在网络上创建不同的节点。或者在同一台机器上使用不同的端口来启动linux查找java进程。我在我的机器上的另一个端口上启动了另一个节点,并将它报了名到我当前的节点上。我有两个节点:? http://localhost:5000? 和 http://localhost:5001? 。Registeringa new?Node然后我在节点2上挖掘了一些新的区块,以担保链更长。我在节点1上调用 GET /nodes/resolve? ,在节点1上的链被共识算法所取代:ConsensusAlgorithm at?Work去找几个朋友测试一下你的Blockchain吧。我希望这能激励你去创造一些新的东西。我对加密货币感到心潮澎湃,因为我相信区块链会迅速改变我们对经济之声在线收听,政府和记要保存的看法。风险警示:蓝狐所有乌有之乡最新文章都不粘连斥资推荐,斥资有风险。建议对项目进行刻骨考察,慎重做好自己的斥资决策。唇齿相依阅读学习区块链的最好方法是构建一个(上)原文小说作者排行榜:Danielvan Flymen原文地址:hackernoon.com译者:由蓝狐笔记社群“iGreenMind”翻译「品牌传销策划公司」

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